What is the approximate width of each lot in a 5 acre parcel divided into 6 equal lots with a depth of 250'?

To determine the approximate width of each lot in a 5-acre parcel divided into 6 equal lots, we first need to convert the area of the parcel to square feet. Since one acre is equal to 43,560 square feet, a 5-acre parcel will be:

5 acres × 43,560 square feet/acre = 218,700 square feet.

Next, since the parcel is to be divided into 6 equal lots, we will divide the total area by 6 to find the area of each lot:

218,700 square feet ÷ 6 = 36,450 square feet per lot.

Now, knowing that each lot has a depth of 250 feet, we can find the width by using the formula for the area of a rectangle (Area = Width × Depth). Rearranging this gives us:

Width = Area / Depth.

Substituting in the values we calculated:

Width = 36,450 square feet ÷ 250 feet = 145.8 feet.

This rounds to approximately 145.2 feet for practical purposes. Thus, this calculation supports that the width of each individual lot is in the vicinity of 145.2 feet, making that the most accurate answer choice.